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因式分解 (x+y)^2-xy(1-x-y)-1
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推荐答案 2008-08-23
(x+y)^2-xy(1-x-y)-1
=(x+y)^2-1-xy(1-x-y)
=(x+y+1)(x+y-1)+xy(x+y-1)
=(x+y-1)(x+y+1+xy)
=(x+y-1)[x(y+1)+(y+1)]
=(x+y-1)(x+1)(y+1)
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第1个回答 2008-08-23
(x+y)^2-xy(1-x-y)-1
=(x+y)^2-1-xy(1-x-y)
=(x+y+1)(x+y-1)+xy(x+y-1)
=(x+y+1+xy)(x+y-1)
=(x+1)(y+1)(x+y-1)
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(x+y)
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答:
解题如下:
(x+y)^2(xy
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