定义一个整形数组,求数组中的元素之和及平均值

Question

如题所述

Answer 1

#include <stdio.h>
#define N 10
int main( )
{
int a[N] = {10,20,30,40,50,60,70,80,90,100};
int i = 0,sum = 0;
for(i = 0;i < N;i++)
{
sum = sum + a[i];
}
printf("元素之和为:%d,平均值为：%f\n",sum,(float)sum/N);
}