哪位老师能编一个在通达信选股器找五线开花的公式

如题所述

第1个回答  2011-06-25
TJ1:=MA(C,5)>REF(MA(C,5),1);
TJ2:=MA(C,10)>REF(MA(C,10),1);
TJ3:=MA(C,20)>REF(MA(C,20),1);
TJ4:=MA(C,30)>REF(MA(C,30),1);
TJ5:=MA(C,60)>REF(MA(C,60),1);
(TJ1+TJ2+TJ3+TJ4+TJ5)>3;
第2个回答  2011-06-25
EMA13:=EMA(C,13);
EMA30:=EMA(C,30);
EMA60:=EMA(C,60);
EMA90:=EMA(C,90);
EMA120:=EMA(C,120);
M1:=1000*EMA30/EMA60<=1115 AND 1000*EMA30/EMA60>=875;
M2:=1000*EMA60/EMA90<=1120 AND 1000*EMA60/EMA90>=880;
M3:=1000*EMA90/EMA120<=1115 AND 1000*EMA90/EMA120>=885;
XG:=M1 AND M2 AND M3 AND CROSS(EMA13,EMA30);
E88:EXIST(XG,2);

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{附:五线开花主图公式}
EMA13:EMA(C,13),COLORFFCCCC;
EMA30:EMA(C,30),COLORYELLOW;
EMA60:EMA(C,60),COLORFF00FF;
EMA90:EMA(C,90),COLORGREEN;
EMA120:EMA(C,120),COLORBLUE;
M1:=1000*EMA30/EMA60<=1115 AND 1000*EMA30/EMA60>=875;
M2:=1000*EMA60/EMA90<=1120 AND 1000*EMA60/EMA90>=880;
M3:=1000*EMA90/EMA120<=1015 AND 1000*EMA90/EMA120>=885;
DRAWICON(M1 AND M2 AND M3 AND CROSS(EMA13,EMA30),L-0.20,9);本回答被网友采纳
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