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求证:cosx •cos2x•cos4x= sin8x 8sinx .
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第1个回答 2022-07-31
证明:由倍角公式sin2x=2sinxcosx,故sin8x=2sin4xcos4x=4sin2xcos2xcos4x=8sinxcosxcos2xcos4x,所以sin8x8sinx.=8sinxcosxcos2xcos4x8sinx=cosx•cos2x•cos4x,故cosx•cos2x•cos4x=sin8x8sinx.得证....
相似回答
求证:sin8x
=
8 sinx
cosx
cos2x
cos4x
答:
做这种题目一般是从复杂的向简单的方向做。所以从右边开始证明
8 sinx
cosx
cos2x
cos4x =4*(2sinx cosx )cos2x cos4x =4*sin2x cos2x cos4x =2*(2sin2x cos2x )cos4x =2sin
4xcos4x =sin8x
等于左边得证
求证:sin8x
=
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cos2x
cos4x
答:
做这种题目一般是从复杂的向简单的方向做.所以从右边开始证明
8 sinx
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cos2x
cos4x =4*(2sinx cosx )cos2x cos4x =4*sin2x cos2x cos4x =2*(2sin2x cos2x )cos4x =2sin
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等于左边得证
求
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三角函数规律问题
答:
cosxcos2xcos4xcos8x
=sinxcosxcos2xcos4xcos
8x/sinx =(1/2)sin
2xcos2xcos4xcos
8x/sinx =(1/4)sin
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cos
π/15 cos(2π/15)cos(3π/15)cos(4π/15)cos(5π/15)cos(6π/15...
答:
注意到以下两个结论:(1)cosxcos2x =4sinxcosxcos2x/[4sinx]=2sin2xcos2x/[4sinx]=sin4x/[4sinx](2)cosxcos2xcos4xcos8x =16
sinxcosxcos2xcos4xcos
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=8sin2xcos2xcos4xcos
8x/[16sinx]=4sin
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sin8xcos
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cosxcos2xcos4x
化简过程
答:
原式乘以
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