第1个回答 2016-11-23
#include<stdio.h>
int main(void) {
int array[] = { 1, 2, 3, 4, 5, 6, 9 };
int count = sizeof(array) / sizeof(array[0]);
printf("\n数组原始数据: ");
for (int i = 0; i < count; i++) {
printf("%d, ", array[i]);
}
int start = 0;
int end = count - 1;
while (start < end) {
int swap = array[start];
array[start] = array[end];
array[end] = swap;
start++;
end--;
}
printf("\n逆序后的数据: ");
for (int i = 0; i < count; i++) {
printf("%d, ", array[i]);
}
}本回答被网友采纳
第2个回答 2016-11-23
#include <stdio.h>
void bg(int *a,int b,int e)
{
if (b>=e)return ;
a[b]+=a[e];
a[e]=a[b]-a[e];
a[b]-=a[e];
bg(a,b+1,e-1);
}
int main(int argc, char* argv[])
{
int i,a[10]={1,2,3,4,5,6,7,8,9,10};
bg(a,0,9);
for (i = 0; i < 10; i++) printf("%d ",a[i]);
return 0;
}