第1个回答 2017-08-07
你好,有的。DIFF:=EMA(CLOSE,12) - EMA(CLOSE,26);DEA := EMA(DIFF,9);MACD := 2*(DIFF-DEA);select:cross(diff,dea) and dea>-1.0 and dea<0.5 and CLOSE>ref(CLOSE,1) and CLOSE>=ma(c,60);
或:
DIF:=EMA(CLOSE,12)-EMA(CLOSE,26); DEA:=EMA(DIF,9); XG:DIF>0 AND DEA>0 AND CROSS(DIF,DEA);
不足之处,多多交流。
第2个回答 2017-08-07
A:=MACD.MACD;
A1:=A>REF(A,1) AND REF(A,1)<REF(A,2);
X:FILTER(A1 AND A<0,15);本回答被提问者采纳