数学题目用因式分解解方程（x-4）²+8（x-4）+16＝0

Question

如题所述

Answer 1

如图，详解

Answer 2

令y=x-4，则有y²+8y+16=0
即(y+4)²=0
所以y=-4，即x-4=-4
所以x=0

Answer 3

图

Answer 4

x-4=(x-4)2 (x-4)2 - (x-4) = 0 (x-4)(x-4-1) = 0 (x-4)(x-5) = 0 x=4 或 x=5 （5x-1)(2x+4)=3x+6 （5x-1)(2x+4) - (3x+6) = 0 2(5x-1)(x+2) - 3(x+2) = 0 (x+2) { 2(5x-1) - 3} = 0 (x+2)(10x-5) =0 (x+2)(2x-1) = 0 x=-2 或 x=1/2 x2-3x-18=0 (x-6)(x+3) = 0 x=6 或 x=-3 2y2-5y+2=0 (2y-1)(y-2) = 0 y=1/2 或 x=2 x2+5=2（根号5）x x2 - 2√5x + 5 = 0 (x-√5)2 = 0 x = √5 重根 (3x+2)2-4x2=0 (3x+2+2x)(3x+2-2x) = 0 (5x+2)(x+2) = 0 x=-2/5 或 x=-2 2x2-mx=15m 2x2-mx-15m = 0 (x-3m)(2x+5m) = 0 x=3m 或 x=-2.5m