(x+y)^2+4(x十y一1)因式分解

Question

如题所述

Answer 1

(x+y)²+4(x+y-1)
=x²+2xy+y²+4x+4y-4
=x²+4x+4+y²+4y+4+2xy-12
=(x+2)²+(y+2)²+2xy-12

Answer 2

追答

核实下题目

Answer 3

(x+y+2)平方-6追答

求采纳

-8

不是-6

再分解就是

(x+y+2+根号8)(x+y+2-根号8)