代码如下
#include <stdio.h>
void main()
{
int ans = 0;
int buff[10] = { 1,2,3,4,5,6,7,8,9,10 },buffn[10];
printf("reverse:");
for (int i = 0; i < 10; i++)
{
*(buffn + i) = *(buff + 9 - i);
printf("%d ", buffn[i]);
ans += *(buff + i);
}
printf("\n");
printf("sum:%d\n", ans);
float average = ans / 10.0;
printf("average:%f\n", average);
}
本回答被网友采纳