代数法化简逻辑函数，

Question

如题所述

Answer 1

F=(C+D)(B+D)(B+C)(A'+D)(A'+B'+C'+D)

=(D+BC)(B+C)(A'+D)(B'+C')

=(D+BC)(BC'+B'C)(A'+D)=(A'+D)(B⊕C)D = (B⊕C)D

最后得到：F = (B⊕C)D

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Answer 2

用A'表示非A,余者类推。
(B+D)(C+D)=BC+D,
同理，(A'+D)(A+B'+C'+D)
=A'(A+B'+C')+D
=A'B'+A'C'+D,
∴F=(B+C)(BC+D)(A'B'+A'C'+D)
=(B+C)[BC(A'B'+A'C')+D]
=(B+C)D
=BD+CD.