由题意可知:
(a) Y=A'B'C+A'BC'+AB'C'
画出相对应的卡诺图,将相邻的两个1算出,当A为0时,BC相反,即B异或C,所以,A'B'C+A'BC'=A'(B异或C),所以由卡诺图可得:
Y=AB'C'+A'(B异或C)
(b)根据题意画出其卡诺图,两个两个一圈,四个四个一圈,如图所示:
第一个圈:当MN为11时,PQ取任意值,即Z1=MN
第二个圈:当PQ为11时,MN取任意值,
即Z2=PQ
第三个圈:当MNP=011时,B为任意值,
即:Z3=M'NP
Z=Z1+Z2+Z3=MN+PQ+M'NP
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