求不定积分∫xe^(x^2)dx?？

Question

如题所述

Answer 1

∫xe^(x^2)dx=(1/2)e^(x^2))+C,6,凑微分∫xe^(-x^2)dx =∫e^(-x^2)d(x^2/2), 因为xdx=d(x^2/2) =-1/2*∫e^(-x^2)d(-x^2) =-1/2*e^(-x^2) -1/2*e^(,2,