2(x-y)的平方-x+y 怎么因式分解

Question

如题所述

Answer 1

2（x-y）²-（x-y）=（x-y）[2(x-y)-1]=(x-y)(2x-2y-1)
Tips:把后面-x+y的负号提出来要变号^0^

Answer 2

原始=2(x-y)²-(x-y)
=(x-y)[2(x-y)-1]
=(x-y)(2x-2y-1)

Answer 3

2(x-y)^2-x+y=2(x-y)^2-(x+y)=[2(x-y)-1](x-y)=(2x-2y-1)(x-y)本回答被提问者采纳

Answer 4

2(x-y)(x-y)-x+y=2(x-y)(x-y)-(x-y)=(2x-2y-1)(x-y)

Answer 5

2(x-y)^2-x+y
=2(x-y)^2-(x-y)
=(x-y)[2(x-y)-1]
=(x-y)(2x-2y-1)