第1个回答 2012-05-17
{突破}
M5:=MA(C,5);
M10:=MA(C,10);
M30:=MA(C,30);
D1:=BARSLAST(CROSS(M5,M10));
D2:=BARSLAST(CROSS(M5,M30));
D3:=BARSLAST(CROSS(M10,M30));
T1:=CROSS(M10,M30);
T2:=D1>=D2 AND D2>=D3;
T3:=COUNT(CROSS(M10,M5) OR CROSS(M30,M10) OR CROSS(M30,M5),D1)=0;
T4:=REF(M5<M30 AND M10<M30,D1+1);
突破:T1 AND T2 AND T3 AND T4;本回答被网友采纳