用汇编语言做大小端的转换代码答:; 字的大小端转换 CODE SEGMENT ASSUME CS:CODE BUF1 DW 1,2,3,4,5,6,7,8,9,0 N EQU ($-BUF1)/2 BUF2 DW N DUP(?) START: PUSH CS POP DS PUSH CS POP ES MOV CX,N ...
有会汇编语言的高手给写下注释,谢谢了……答:stack segment stack dw 256 dup(?)stack ends ;定义256个字单无的栈空间 data1 segment year db 5,?,6 dup(0)org 10h var dw 0 yes db "yes!",13,10,'$'no db "no!",13,10,'$'data1 ends ;定义字符串 code1 segment assume cs:code1,ds:data1 start:mov ax,data1 mov ds...
汇编语言 输出12345,45678,56451(代码)答:;输出12345,45678,56451 wert segment xy dw 12345,45678,56451 mn db 5 dup(?)wert ends gg segment assume cs:gg,ds:wert main proc near start:mov ax,wert mov ds,ax mov si,offset xy mov bp,3 nx1:call show mov ax,0e20h int 10h add si,2 dec bp jnz nx1 mov ah,7 int...
用汇编语言编程答:;输入任意字符串string,点击Enter 结束输入;;将字符串string 中的大写字母转换为小写字母输出,;按回车键结束。DATA SEGMENT BUF1 DB 'Please input random string,end with Enter key:$';提示输入 BUF2 DB 0,0,0,0,0,0,0,0,0,0,0DH;存放输入的字符,假设最多10个字符 NUM1 DW 0;实际...