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2(x-3)²=x²
2(x-3)
的平方
=x
的平方-9
答:
2(x-3)
^2
=x
^2-9 x^2-12x+27=0 (x-3)(x-9)=0
x=
3 or 9
2(x-3)=
2x-6 方程
答:
2x-6
=x
+
2
x=8
一元二次方程
2(x-3)
²
=x
(x-3)用式分解法分解后仍然是一元二次方程...
答:
解:
2(x-3)
²-x
(x-3)=
0 (x-3)(2x-6-x)=0 (x-3)(x-6)=0 ∴x-3=0 x-6=0 ∴x1=3
x2
=6
2(x-3)=
5
答:
你好
2(x-3)=
5 x-3=5÷2
x=
2.5+3 x=5.5 如有不明白,可以追问如有帮助,记得采纳。谢谢 祝学习进步!
2(x-3)
²
=x
-3用配方法
答:
2(x-3)
²
=x
-3 2(x-3)²-
(x-3)=
0 (x-3)[2(x-3)-1]=0 (x-3)(2x-7)=0 x1=3,
x2
=3.5
2(x-3)
⊃2;
=x
⊃2;-9 怎么用分解因式法解
答:
1、
2(x-3)
²
=x
²-9 解:2(x-3)²=(x-3)(x+3)2(x-3)²-(x-3)(x+
3)=
0 (x-3)(
2(x-3)
-(x+3))=0 (x-3)(x-9)=0 得,x1=3,
x2
=9 2、9(2x+3)²-4(2x-5)²=0 解:(3(2x+3))²-(2(2x-5))&...
2(x-3)
的平方
=x
的平方-9怎么算啊!考试急啊
答:
按你的描述应该是:解:2(x-3)^2 =x^2-9 2(x-3)^2=(x-3)(x+3)所以,x=3 时满足要求;x不等于3时,等式两边消去“x-3”得:
2(x-3)= x
+3 解得x=9 最后解得:x=3 或者9
用因式分解法解方程
2(x-3)
的平方
=x
的平方-9
答:
2(x-3)
²-(x²一3²)=0 2(x-3)²一(x+3)
(x-3)=
0 (x一3)〔2(x-3)一(x+3)〕=0 (x-3)(2x-6-x-3)=0 (x-3)(x-9)=0 x-3=0,
x=
3 x一9=0,x=9 ...
2(x-3)
的平方
=x
-3
答:
2(x-3)
的平方
=x(x-3) =
=
2(x -3)
^2
= x
(x - 3)=
=
2(x - 3)
^2 - x(x-3) =0 == (x - 3)[2(x - 3) - x)] = 0 == (x -3)[2x - 6 - x] = 0 == (x - 3)(x - 6) = 0 == x = 3, 6 ...
2(x-3)
²
=x
²-9
答:
2(x-3)²=x²-9 2(x-3)²=(x+3)(x-3)两边有公因式x-3,当x-3=0,x=3时,是方程的解。如果x-3不等于0,两边除以x-3
2(x-3)=x
+3 2x-6=x+3 x=9.所以有2个解x=9, x=3
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