定义一个10个整形数组输入一个数 查找此数组中有无此数 若有输出此数...答:include <stdio.h>int find(int arr[], int n, int key){int i;for(i=0; i<n; i++){if(arr[i] == key){return i;}}return -1;}void main(){int arr[] = {49, 38, 65, 97, 76, 13, 27, 9, 18, 30};int n = 10;int key;int pos;printf("请输入待查找数:")...